Physics, asked by vamugsw3157, 1 year ago

Water flows through a pipe of varying cross sectional area of 30cm2 and 15 cm2. The pressure change with the pipe is 600n/m2. Find the rate of flow of water through the pipe

Answers

Answered by LostInJordan
0

Volume of water flowing per second = R

= 15 / 60

= 0.25 m^3/s

R = Av

A = R / v

A = 0.25 / 3

A = 1/12 m^2

Area of cross section is 1/12 m^2

Radius of pipe = sqrt(1/(12 * π)) ……[∵ A = πr^2]

= 0.162 m

= 16.2 cm

Answered by naveenjai2004
0

Answer:

16.2 cm

Explanation:

Volume of water flowing per second = R

= 15 / 60

= 0.25 m^3/s

R = Av

A = R / v

A = 0.25 / 3

A = 1/12 m^2

Area of cross section is 1/12 m^2

Radius of pipe = sqrt(1/(12 * π)) ……[∵ A = πr^2]

= 0.162 m

= 16.2 cm

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