Water has a refractive index of 1.33 and air has refractive index of 1.00 find the critical angle for a water air boundary
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Answered by
2
Explanation:
Correct option is
C
48
∘
45
1
From snells law we have
a
u
w
=
sini
c
1
,
sini
c
=
a
u
w
1
=
1⋅33
1
i
c
=48
∘
45
1
.
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