Water has to be lifted to a height of 30m from an underground sump at the rate of 10 liters/s. Consider that there are no losses in the system .Calculate the power required by the prime mover(5)
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Explanation Density of water=1kg/l
So 10 l water masses 10 kg
Now 10 kg water weighs 100N=Force
Workdone against gravity=mgh
=10×10×30=3000J
Since 1 litre of water transported per second,3000j work is done per second so
Power =w/t=3000J/sec=3000watt
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