Physics, asked by mfauuch786, 1 month ago

: Water ideally flows through a pipe of radius of 6 cm at a rate of 5m/s. the pipe then narrows to a radius of 2 cm. what is the new velocity of the water

Answers

Answered by amitnrw
1

Given : Water ideally flows through a pipe of radius of 6 cm at a rate of 5m/s. the pipe then narrows to a radius of 2 cm.

To Find : what is the new velocity of the water

Solution:

Water ideally flows through a pipe of radius of 6 cm at a rate of 5m/s.

Cross-section area = πr²  = π(6)²  = 36π  cm²

velocity  = 5 m/s

pipe then narrows to a radius of 2 cm.

Cross-section area = πr²  = π(2)²  = 4π  cm²

new velocity = V m/s

Cross-section area *  velocity    = Constant

=> 4π  * V = 36π * 5

=> V = 45  

new velocity of the water = 45 m/s

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Answered by DoctörSmíle
1

Given : Water ideally flows through a pipe of radius of 6 cm at a rate of 5m/s. the pipe then narrows to a radius of 2 cm.

To Find : what is the new velocity of the water

Solution:

Water ideally flows through a pipe of radius of 6 cm at a rate of 5m/s.

Cross-section area = πr²  = π(6)²  = 36π  cm²

velocity  = 5 m/s

pipe then narrows to a radius of 2 cm.

Cross-section area = πr²  = π(2)²  = 4π  cm²

new velocity = V m/s

Cross-section area *  velocity    = Constant

=> 4π  * V = 36π * 5

=> V = 45  

new velocity of the water = 45 m/s

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