Question

Water if flowing at of rate of 15 km/hr through a pipe of diameter 14 cm into a cubical pond which is 50 m long and 44 m wide. In what time will the level of water in pond rise by 21 cm ?

Answer 1

$\huge\mathfrak\purple{ANSWER}$

Given diameter of cylinder = 14 cm

Therefore radius of cylinder, r = 7 cm

Volume of cylinder = πr²h cubic units

Volume of water flowing through the cylindrical pipe in 1 hour at the rate of 15km/hr = (22/7) x (7/100) x (7/100) x 15000 = 231 cu m

We know that volume of cuboid = lbh cubic units

Therefore volume of water in the tank = 54 x 44 x (21/100) = 462 cu m Time taken = (462/231) = 2 hours

Answer 2

Question:

→ Water is flowing at the rate of 15 km/h through a pipe of diameter 14 cm into a cuboidal which is 50m long and 44m wide. In what time will the level of water in pond raise by 21cm.

Answer:

→ Time = 2 hours .

Step-by-step explanation:

Suppose, the level of water in the pond rises by 21 cm in 'x' hours.

→ Speed of water flowing through a pipe = 15 km/hr .

→ Diameter of the pipe = 14/100 m  .

Then, Radius of the pipe (r) = 7/100 m  .

∵ Volume of water flowing out of the pipe in 1 hour

= πr²h  .

= (22/7) x (7/100) x (7/100) x 15000  .

= 231 m³ .

→  

Volume of water flowing out of the pipe in 'x' hours = 231x m³.

∵ Volume of water in the cuboidal pond  = lbh .

= 50 x 44 x (21/100)  .

= 462 m³ .

∵ Volume of water flowing out of the pipe in 'x' hours  = Volume of water in the cuboidal pond  raised by 21 cm .

∵  231x  = 462 .

⇒ x = $\frac{462}{231}$ .

∴ x = 2  .

Therefore, the required time is 2 hours.

✔✔ Hence, it is solved .✅✅

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