Physics, asked by Anonymous, 10 months ago

Water in a bucket tied with rope is whirled
around in a vertical circle of radius 0.5 m.
Calculate the minimum velocity at the
lowest point so that the water does not
spill from it in the course of motion.
(g = 10 ms)

Answers

Answered by unmitchauhan03
2

Answer:

A bucket is tied and rotated around a vertical circle whose radius is given as,

r = 0.5 m

We know that in a circular vertical motion the velocity changes from point to point.  

Also, the formula for the minimum velocity at the lowest point so that the water does not spill from the bucket in the course of motion is given as,

=

taking g = 10 m/s² and r = 0.5 m

=

=

= 5 m/s

Thus, the minimum velocity at the lowest point so that the water does not spill from it in the course of motion is 5 m/s.

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Explanation:

Answered by arenarohith
5

Answer:

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