Question

water in a bucket tied with rope whirled around in a vertical circle of radius 0.5m calculate the minimum velocity at the lowest point so that the water does no spill from it in the course of motion g=10 m second square

Answer 1

Answer:

एसएफएफबीएफएंडह &;&;*!&*":*;*++ सकॉलरशिप दुहू

Answer 2

Answer: 5 m/s

Explanation:

A bucket is tied and rotated around a vertical circle whose radius is given as,

r = 0.5 m

We know that in a circular vertical motion the velocity changes from point to point.  

Also, the formula for the minimum velocity at the lowest point so that the water does not spill from the bucket in the course of motion is given as,

= $\sqrt{5*r*g}$

taking g = 10 m/s² and r = 0.5 m

= $\sqrt{5 * 0.5 * 10}$

= $\sqrt{25}$

= 5 m/s

Thus, the minimum velocity at the lowest point so that the water does not spill from it in the course of motion is 5 m/s.