Water in a canal, 30 dm wide and 12 dm deep, is flowing with a speed of 10 km/hr. How much area will it irrigate in 30 minutes
Answers
Answered by
15
measurements of canal=
l=10000m
b=30m
h=12m
water flow in 1 hr
=lbh
=10000×30×12
=3600000m³
water falling in 30 min=3600000/2
=1800000m3
l=10000m
b=30m
h=12m
water flow in 1 hr
=lbh
=10000×30×12
=3600000m³
water falling in 30 min=3600000/2
=1800000m3
yashasvi019:
sorry i didn't recognise that it was dm
Answered by
35
Converting dm into m we know that,
1 dm = 1/10 m
30 dm = 30/10 m = 3 m
12 dm = 12/10 m = 1.2 m
Volume of water that flow from canal,
= 3 m × 1.2 m × 10 km/h
= 3 m × 1.2 m × 10 × 1000 m/h
= 3.6 m² × 10000 m/h
= 36000 m³/h
This volume of water accumulated for 30 mins
= 36000 m³/h × 30/60 hr
= 18000 m³
Since area × height = volume
Area = Volume/height
Area = 18,000 m³/ height in m
Area = 18000/h m²
Since you have not mentioned value of h.
So if you have forgotten to type whole question, then just put value of h.
1 dm = 1/10 m
30 dm = 30/10 m = 3 m
12 dm = 12/10 m = 1.2 m
Volume of water that flow from canal,
= 3 m × 1.2 m × 10 km/h
= 3 m × 1.2 m × 10 × 1000 m/h
= 3.6 m² × 10000 m/h
= 36000 m³/h
This volume of water accumulated for 30 mins
= 36000 m³/h × 30/60 hr
= 18000 m³
Since area × height = volume
Area = Volume/height
Area = 18,000 m³/ height in m
Area = 18000/h m²
Since you have not mentioned value of h.
So if you have forgotten to type whole question, then just put value of h.
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