Water in a canal, 30 dm wide
and 24 dm deep is flowing
with velocity of 20 km/hr. How
much area will it irrigate in 30
minutes, if 8 cm of standings
water is required for irrigation?
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Answer:
Velocity of water=20Km/h
Water in the canal forms a cuboid of breadth = 12dm=
10
12
m=1.2m
Height = 30dm=
10
30
m=3m
Length = Distance covered by water in 30 minutes
= Velocity of water × time
=20000×
60
30
=10000 m
Therefore,
Volume of water flown in 30 min = lbh=(1.2×3×10000)=36000 m
3
Suppose area irrigated be A m
2
. Then,
A×
100
9
= Volume flown in 30 minutes
A×
100
9
=36000
A=400000 m
2
Hence, area irrigated =400000 m square
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