water in a canal 30m wide and 12m deep is flowing with a velocity of 10km/hr. How much area will it irrigate if 16cm of standing water is required
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Answered by
34
Volume of water in the canal = l * b * h
= 30*12*10000 = 36,00,000 cubic meter
36,00,o00 cubic meter water flows in 1 hour.
Area of the plot = l * b
Volume = l * b*h = 36,00,000
=> l * b * 0.16 = 36,00,000
=> l * b = 36,00,000/ 0.16
=> l * b= 2,25,000 square m
Therefore an area of 2,25,000 square meter will be irrigated
= 30*12*10000 = 36,00,000 cubic meter
36,00,o00 cubic meter water flows in 1 hour.
Area of the plot = l * b
Volume = l * b*h = 36,00,000
=> l * b * 0.16 = 36,00,000
=> l * b = 36,00,000/ 0.16
=> l * b= 2,25,000 square m
Therefore an area of 2,25,000 square meter will be irrigated
Answered by
10
Answer
Step-by-step explanation:
SolutionWidth of the canal = 30 dm = 300 cm = 3 m
Depth of the canal 12 cm = 120 cm = 1.2 m
It is given that the water is flowing with velocity 10 km/hr
Therefore Length of the water column formed is 1/2 hour = 5 km = 5000 m
Therefore volume of the water flowing in 1 hour
= Volume of the cuboid of length 5000 m, width 3 m and depth 1.2 m
=> Volume of the water in half hour = (5000*3*1.2) m^3 = 18000 m^3
Suppose x m^2 area is irrigated in 1/2 hour
x*8/100 = 18000
x = 1800000/8
x = 225000
Hence the canal irrigated 225000 m^2 area in 1/2 hours
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