Water in a canal, 30m wide and 12m deep is flowing with a velocity of 10kmph. how much area will it irrigate in 30min if 8 cm of standing water is required for irrigation
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We have,
Width of the canal=30dm=300cm=3m
Depth of the canal=12dm=120cm=1.2m
It is given that the water is flowing with a velocity 10km/hr.
Therefore length of the water column formed in
2
1
hour=5km=5000m
volume of the water flowing in
2
1
hour
= Volume of the cuboid of length 5000m, width 3m and depth 1.2m
Volume of the water following in
2
1
hour
=5000×3×1.2m
3
=18000m
3
Suppose x m
2
area is irrigated in
2
1
hour. Then
x×
100
8
=18000
⇒x=225000m
2
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