Math, asked by Arshippk13, 11 months ago

Water in a canal 30m wide and 12m deep is flowing with a velocity of 20km/h . How much area will it irrigated in 30 min if 9 cm of standing water is desired ?

Answers

Answered by monuthoppil
2

Answer:

Step-by-step explanation:

Width of the canal = 30 dm = 300 cm = 3 m

Depth of the canal 12 cm = 120 cm = 1.2 m

It is given that the water is flowing with velocity 10 km/hr

Therefore Length of the water column formed is 1/2 hour = 5 km = 5000 m

Therefore volume of the water flowing in 1 hour

= Volume of the cuboid of length 5000 m, width 3 m and depth 1.2 m

=> Volume of the water in half hour = (5000*3*1.2) m^3 = 18000 m^3

Suppose x m^2 area is irrigated in 1/2 hour

x*8/100 = 18000

x = 1800000/8

x = 225000

Hence the canal irrigated 225000 m^2 area in 1/2 hours


Arshippk13: i am sorry to say but the depth and the width is given in metres
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