Water in a canal, 6 m wide and 1.5 m deep, is
flowing at a speed of 4 km/h. How much area
will it irrigate in 10 minutes if 8 cm of standing
water is needed for irrigation? (CBSE 2014)
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Answer:
the required area is 187500 m²
Step-by-step explanation:
area of cross-section = 6×1.5
=9m²
speed of water=10km/h = 10×1000/60 m/min
volume of water that flows in 1min from canal=9×10000/60 = 1500m³
volume of water that flows in 10 mins from canal =1500×10 = 15000m³
let the irrigated area be x.
volume of water flowing in 10 mins from canal= volume of water irrigating the required area
15000=A×8cm
15000=A×8/100 m
15000×100/8 =A
⇒A= 187500m²
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