Question

Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of
10 km/h. How much area will it irrigate in 30 minutes if 8 cm of standing
water is needed ? ​

Answer 1

Step-by-step explanation:

$canal \: is \: the \: shape \: where... \\breadth \: = 6m \\ height \: = 1.5m \\ and \: speed \: of \: water \: flowing \: \\ in \: the \: canal = 10 \: kmph$

$length \: of \: canal \: in \: one \: hour \\ = 10 \: km$

$length \: of \: canal \: in \: 60 \: minutes \\ = 10 \: km$

$length \: of \: canal \: in \: 1 \: minute \\ = \frac{1}{60} \times 10$

$length \: of \: canal \: in \: 30 \: minutes \\ = \frac{30}{60} \times 10 \\ = 5 \: km \\ = 5000 \: m$

$now \: volume \: of \: canal \\ = length \times breadth \times height$

$= 5000 \times 6 \times 1.5 \: {m}^{3}$

$now \: volume \: of \: water \: in \: canal \\ = volume \: of \: area \: irrigated$

$volume \: of \: water \: in \: canal \\ = area \: irrigated \: \times height$

$5000 \times 6 \times 1.5 \: {m}^{3} \\ = are \: irrigated \: \times \: 8 \: cm$