Question

Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed?

Answer 1

Speed of flowing of water from canal is 10km/h , means length of water flows in 1 hour = 5 km , so length of water flows in 30 minutes = 5km 


Now, volume of water flowing from canal = length of water flows in 30 minutes × breadth of canal × deep of canal 
= 5000m × 6m × 1.5m = 45000 m³ 

Let area of field = x m² 
Then, volume of water irrigates into the field = area of field × height of water during irrigation 
= x m² × 8× 10⁻² m = 0.08x m³ 

Now, volume of water flowing from canal = volume of water in field 
45000 m³ = 0.08x m³ 
x = 562500 m²

We know, 1 hectare = 10000 m² 
So, area of field in hectare = 562500/10000 = 56.25 hectares

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Answer 2

width =6m
depth =1.5m
the length of water column formed in 30 min =10/2=5km=5000m
volume of water flowing in 30 min
=6*1.5*5000
let the water irrigate the area xm
height =8cm=0.08m
x=6*1.5*5000/0.08=562500m