Math, asked by itslisa07, 17 days ago

Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed.

Answers

Answered by vt2079030
0

Answer:

Canal is the shape of cuboid where

Breadth = 6 m

Height = 1.5 m

& Speed of canal = 10 km/hr

Speed 10 km/h

h = 1.5 m

b=6m

Length of canal in 1 hour = 10 km

Length of canal in 60 minutes = 10 km

Length of canal in 1 min =

60

x 10 km

30

Length of canal in 30 min = 30/60x 10 = 5km = 5000 m

Step-by-step explanation:

I hope it will hel u

Answered by prajapatisaroj415
2

Answer:

Canal is in the shape of cuboid , where,

Breadth =6 m

Height =1.5 m

Speed of canal =10 km/hr

Length of canal in 1 hour =10 km

Length of canal in 60 minutes =10 km

Length of canal in 1 minute =

60

1

×10 km

Length of canal in 30 minute =

60

30

×10=5km=5000 m

Now,

Volume of canal = length×breadth×height

= 5000×6×1.5 m

3

Now,

Volume of water in canal = Volume of area irrigated

Volume of water in canal = Area irrigated × Height

5000×6×1.5 = Area irrigated ×

100

8

Area irrigated =

8

5000×6×1.5×100

Area irrigated = 562500 m

2

Area irrigated =

10000

562500

hectares

Area irrigated = 56.25 hectares

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