Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed.
Answers
Answered by
0
Answer:
Canal is the shape of cuboid where
Breadth = 6 m
Height = 1.5 m
& Speed of canal = 10 km/hr
Speed 10 km/h
h = 1.5 m
b=6m
Length of canal in 1 hour = 10 km
Length of canal in 60 minutes = 10 km
Length of canal in 1 min =
60
x 10 km
30
Length of canal in 30 min = 30/60x 10 = 5km = 5000 m
Step-by-step explanation:
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Answered by
2
Answer:
Canal is in the shape of cuboid , where,
Breadth =6 m
Height =1.5 m
Speed of canal =10 km/hr
Length of canal in 1 hour =10 km
Length of canal in 60 minutes =10 km
Length of canal in 1 minute =
60
1
×10 km
Length of canal in 30 minute =
60
30
×10=5km=5000 m
Now,
Volume of canal = length×breadth×height
= 5000×6×1.5 m
3
Now,
Volume of water in canal = Volume of area irrigated
Volume of water in canal = Area irrigated × Height
5000×6×1.5 = Area irrigated ×
100
8
Area irrigated =
8
5000×6×1.5×100
Area irrigated = 562500 m
2
Area irrigated =
10000
562500
hectares
Area irrigated = 56.25 hectares
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