Math, asked by elamathi87, 1 year ago

water in a Canal 6M wide 1.5 m deep is flowing with the speed of 10 km per hour how much area will it irrigate in 30 minutes if 8 cm of standing water is needed

Answers

Answered by deepakastro
6
speed = 10km/h

L = 1000m/h

L = 1000/60

Volume of pipe = Area × h

lbh × time = Area ×h

1000/60 × 6 × 1.5 × 30 = Area × 8

4500 = Area × 8

Area = 4500/8

Area = 562.5 cm^2

deepakastro: Hope it helps
Answered by wwwarshpundir2003
10

Answer:


Step-by-step explanation:

Breadth(b)=6m

Height(h)=1.5m

Length(l)=10×1000/60 m

Now,volume of the water in 30 minutes=lbh×30min

30×6×1.5×10×1000/60

30×15000

45000m³

Let the area of the standing water be a

Hence,a×0.08=45000

a=4500/0.08

a=562500m²

Good morning....


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