water in a Canal 6M wide 1.5 m deep is flowing with the speed of 10 km per hour how much area will it irrigate in 30 minutes if 8 cm of standing water is needed
Answers
Answered by
6
speed = 10km/h
L = 1000m/h
L = 1000/60
Volume of pipe = Area × h
lbh × time = Area ×h
1000/60 × 6 × 1.5 × 30 = Area × 8
4500 = Area × 8
Area = 4500/8
Area = 562.5 cm^2
L = 1000m/h
L = 1000/60
Volume of pipe = Area × h
lbh × time = Area ×h
1000/60 × 6 × 1.5 × 30 = Area × 8
4500 = Area × 8
Area = 4500/8
Area = 562.5 cm^2
deepakastro:
Hope it helps
Answered by
10
Answer:
Step-by-step explanation:
Breadth(b)=6m
Height(h)=1.5m
Length(l)=10×1000/60 m
Now,volume of the water in 30 minutes=lbh×30min
30×6×1.5×10×1000/60
30×15000
45000m³
Let the area of the standing water be a
Hence,a×0.08=45000
a=4500/0.08
a=562500m²
Good morning....
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