Question

Water in a Canal 6m wide and 1.5 m Deep is flowing at a speed of 4 km per hour how much area will it irrigate in 10 minutes if 8 cm of standing water is needed for irrigation?

Answer 1

Answer:

52,50,000 m^2

Step-by-step explanation:

Canal is cuboid in shape.

Speed = 4 km/hr

Breadth = 6 m

Height = 1.5 m

Length of canal for 1 hr = 4 km

So, length in 1 min = 4 / 60 km = 1 / 15 km

Length in 10 mins  = 2/3 km =  2000/3 m

Volume of canal = l x b x h = 2000/3 x 6 x 1.5

Irrigated area volume = Volume of canal

Area irrigated x Height = 2000/3 x 6 x 1.5

Irrigated area  = 2000/3 x 6 x 1.5 x 100/8

Irrigated area = 52,50,000 m^2

Answer 2

$\huge\mathcal\red{Question}$

Water in a Canal 6m wide and 1.5 m Deep is flowing at a speed of 4 km per hour how much area will it irrigate in 10 minutes if 8 cm of standing water is needed for irrigation?

${ \huge\fbox \pink {A}\fbox \blue {n} \fbox \purple {s} \fbox \green{w} \fbox \red {e} \fbox \orange {r}}$

Width of Canal = 6m

Depth of Canal = 1.5 m

Speed of water = 10 km/hr

= 1000/60 m/min

Volume of water in 1 min = 6 × 1.5 × 1000/60

= 1500 m³

Therefore, the volume of water in 10 min

= (10 × 1500) m³

= 15000 m³

Let the area of irrigated field be A m²

Therefore, volume of water from Canal in 10 min = volume of water in the field

$= ) \: 15000 = \: \frac{A \: \ \times \: 8}{100} \\ \\ A = \frac{15000 \times 100}{8} \\ A = 187500 \: {m}^{2}$

Hence, it irrigates 187500 m² in 10 min.

I hope it helps you ^_^