Question

Water in a canal,6m wide and 1.5 m deep is flowing with a speed of 10 km/hr., if 8cm of standing water is needed ​

Answer 1

Answer:

Canal is the shape of cuboid where

Breadth = 6m

Height = 1.5m

& Speed of canal = 10 km/hr

Length of canal in 1 hour = 10 km

Length of canal in 60 minutes = 10 km

Length of canal in 1 min = 1/60*10 km

Length of canal in 30 min = 30/60*10 = 5km = 5000 m

Now,

Volume of canal=Length×Breadth×Height

=5000×6×1.5 m³

Now,

Volume of water in canal=Volume of area irrigated

Volume of water in canal=Area irrigated×Height

5000×6×1.5 m³=Area irrigated×8cm

5000×6×1.5 m³=Area irrigated×8/100m

5000*6*1.5*100/100=Area irrigated

Area irrigated=562500m²

Area irrigated=562500/10000 hectares

Area irrigated=56.25 hectares

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Answer 2

Correct Question :

Water in a canal, 6m wide and 1.5 m deep, is flowing with speed of 10km/hr .How much area will it irrigate in 30 minutes ; if 8 cm is standing water is needed?

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$\bf Given\begin{cases} & \sf{ Breadth \; of \; canal \; = 6 \;m } \\ & \sf {Height \;of\; canal \; = 1.5 \;m} \end{cases}$

$\bf { To \; find:}$

• Area irrigated in 30 min

$\bf {Solution :}$

• Length of canal covered in 60 min = 10 km.

• Length of canal covered in 1 min =$\sf {\dfrac {1}{60} \times {10 \: km}}$

• Length of canal covered in 30 min = $\sf {\dfrac {30}{60} \times 100 = 5 \: km = 5000 \: m }$

Volume of canal = volume of cuboid

$\boxed {\small {\frak {\underline {\green{ Volume \; of \; cuboid \; = l \times b \times h}}}}}$

$\implies \sf { 5000 \times 6 \times \ 1.5 }$

$\implies \sf {45000 m^3 }$

Volume of canal = volume of area irrigated

$\implies \sf { 45000 = area \; irrigated \times 8 \: cm }$

$\implies \sf { 45000= area \: irrigated \times \dfrac {8}{100} }$

$\implies \sf { Area \; irrigated = 562500m^2}$

$\boxed {\frak {\pink {Area \; irrigated = 56.26 \; hectares }}}$