Question

Water in a canal 6m wide and 1.5 m deep is flowing with a speed of 10 km per hour how much area will it irrigate in 30 minutes if 8 cm is standing water is needed

Answer 1

speed (S) = 10 km / hr

= 1000000cm/60 min

= 50000cm/3min

time(T) = 30 min

CANAL

B= 6m = 600 cm

H = 1.5m = 150 cm

FIELD

h= 8 cm

area = a

S*T*B*H = a*h

50000 X 30 X 600 X 150 / 3 = 8a

a= 506250000cm^2

a= 50625m^2

Answer 2

$\huge\mathcal\red{Question}$

Water in a canal 6m wide and 1.5 m deep is flowing with a speed of 10 km per hour how much area will it irrigate in 30 minutes if 8 cm is standing water is needed

$\huge\mathcal\purple{Answer}$

Width of Canal = 6m

Depth of Canal = 1.5 m

Speed of water = 10 km/hr

= 1000/60 m/min

Volume of water in 1 min = 6 × 1.5 × 1000/60

= 1500 m³

Therefore, the volume of water in 30 min

= (30 × 1500) m³

= 45000 m³

Let the area of irrigated field be A m²

Therefore, volume of water from Canal in 30 min = volume of water in the field

$= ) \: 45000 = \: \frac{A \: \ \times \: 8}{100} \\ \\ A = \frac{45000 \times 100}{8} \\ A = 562500 \: {m}^{2}$

Hence, it irrigates 562500 m² in 30 min.

I hope it helps you ^_^