Water in a canal, 6m wide and 1.5m deep, is flowing with a speed of 10km/h . How much area will it irrigate in 30 minutes, if 8cm of standing water is needed
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Answered by
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Speed of flowing of water from canal is 10km/h , means length of water flows in 1 hour = 5 km , so length of water flows in 30 minutes = 5km
Now, volume of water flowing from canal = length of water flows in 30 minutes × breadth of canal × deep of canal
= 5000m × 6m × 1.5m = 45000 m³
Let area of field = x m²
Then, volume of water irrigates into the field = area of field × height of water during irrigation
= x m² × 8× 10⁻² m = 0.08x m³
Now, volume of water flowing from canal = volume of water in field
45000 m³ = 0.08x m³
x = 562500 m²
We know, 1 hectare = 10000 m²
So, area of field in hectare = 562500/10000 = 56.25 hectares
hope this helps you......^_-
Answered by
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Width-6m
Depth-1.5m
Speed-10km/h
Water flow in 30 minutes-10/2=5km=5000m
Volume of water flow in 30 minutes=6*1.5*5000=45000 cubic meter
Standing water depth-8 cm =0.08m
Irrigated area=45000/0.08=562500 cubic meter
=562500/10000=56.25 hectares
Depth-1.5m
Speed-10km/h
Water flow in 30 minutes-10/2=5km=5000m
Volume of water flow in 30 minutes=6*1.5*5000=45000 cubic meter
Standing water depth-8 cm =0.08m
Irrigated area=45000/0.08=562500 cubic meter
=562500/10000=56.25 hectares
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