Question

water in a Canal of 3 M wide and 1.2 M deep is flowing with a velocity of 20 km per hour how much area will it irrigate in 30 minutes is 9 CM of standing water is desired

Answer 1

Answer:

400000 $m^{3}$

Step-by-step explanation:

Speed of flowing water= 20 km/h or 1000/3 m/min

Therefore,

Water flowing through canal in one minute= l*b*h

                                                                       =1000/3 * 1.2 * 3

                                                                        =1200 $m^{3}$

Now,

Area irrigated by water = Volume of water/ Height of Standing Water

                                       = 36000/0.09 $m^{3}$

                                       = 400000 $m^{3}$