water in canal 3m wide and 1.2m deep flowing with a speed of 10 km/hr. how much area will it irrigate in 30 minutes if 8cm of standing water is required?
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Answered by
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Volume of water flowing in 30 min = 3 × 1.2 × 10000 × 30 / 60 = 18000 cubic m
Area irrigated = 18000 / 0.08
= 225000 sq. m
Hope this helps!!!
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Area irrigated = 18000 / 0.08
= 225000 sq. m
Hope this helps!!!
Plsss make it the brainliest!!!
oflakes:
i made it brainliest cause u asked
Answered by
0
Given:
Measurement of canal = 3m wide and 1.2m deep
Speed = 10km/hr
Time = 30 minutes
Standing water = 8cm
To Find:
Area that will be irrigated
Solution:
Speed = 10km/hr, converting it into m/h
= 10,000
Time = 30 mins = 0.5h
Standing water required = 8cm = 0.08m
Let the area be = xm²
Calculating -
= 1.2 × 3 × 10,000 × 0.5 h = x × 0.08
= 18000 = x × 0.08
x = 18000/0.08
= 225000
Answer: The area that will be irrigated is 225000m²
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