Math, asked by bheemannakaradi3943, 1 year ago

Water in canal 6m wide and 1.5m deep is flowing with a speed of 10km per hour how much area will it irrigate in 30 min if 8cm of standing water is needed

Answers

Answered by Anonymous
18

Answer :

56.25 hectares.

Step-by-step explanation:

» A.T.Q.

Breadth = 6 m

Height = 1.5 m

Speed of canal = 10 km/hr.

Standing water = 8 cm (height) = 8 × 10-² m

Now

Length of water flowing per hour = 10 km

Length of water flowing in half hour = 10/2

=> 5 km = 5000 m

Volume of water in canal = l × b × h

\implies 5000 m × 6 m × 1.5 m

\implies 45000 m³

________________________________

• Now

Volume of water in canal = Volume of area irrigated

45000 = Area irrigated × h (height)

45000 = Area irrigated × 8 × 10-²

Area irrigated = \dfrac{45000}{8 \:  \times  \:  {10}^{ - 2} }

=> \dfrac{45000\:\times\:{10}^{2}}{8 }

=> 562500 m²

_________________________________

* Point to remember :

  • 10000 = 1 hectare

  • 1 = \dfrac{1}{10000} hectare

_________________________________

=> \dfrac{562500}{10000}

\boxed{56.25\:hectare}

__________________[ANSWER]


Anonymous: thanks :p
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