Physics, asked by cuteprincess200012, 4 months ago

water is ejecting from a pipe of diameter 2 cm with constant velocity of 20cm/s . find out force acting on water??​

Answers

Answered by prabhas24480
1

F = density × area ×velocity

2

Convert V to m/s:

20/100=0.2

=0.2m/s

Density of water =1000

m

3

kg

Convert the diameter length to be in meters :

20/100=0.2

Area of the outlet :

3.142×(0.2/2)

2

=3.142×0.1

2

=0.03142

Doing the substitution :

F=1000×0.03142×0.2

2

=1.2568

Answered by jeonjk0
1

Answer:

F = density × area ×velocity²

Convert V to m/s:

20/100=0.2=0.2m/s

Density of water =1000 kg/m³

Convert the diameter length to be in meters :

20/100=0.2

Area of the outlet :

3.142×(0.2/2)²=3.142×0.1 ² =0.03142

Doing the substitution :

F=1000×0.03142×0.2² =1.2568

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