Water is falling on the Blades of a turbine at the rate of 6 * 103 kg per minure .
The height of the fall is 10 m . Claculate the power given to the turbine. Take g = 10 m/s2
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Answered by
46
ur answer will be :-
h = 10m
g = 10m/s 2
m = 6×103 kg per minute
(*) by putting the values in the formula we have :-
p (power) = w (work done)/ t (Time )
p = mgh/ t
= ( 6*10^3/60) × 10 × 10
= 10.3 × 10 × 10
= 1,030 W
HOPE THIS HELPS.......
h = 10m
g = 10m/s 2
m = 6×103 kg per minute
(*) by putting the values in the formula we have :-
p (power) = w (work done)/ t (Time )
p = mgh/ t
= ( 6*10^3/60) × 10 × 10
= 10.3 × 10 × 10
= 1,030 W
HOPE THIS HELPS.......
Answered by
26
h = 10m
g = 10m/s 2
m = 6×103 kg per minute
(*) by putting the values in the formula we have :-
p (power) = w (work done)/ t (Time )
p = mgh/ t
p= 6* 10^3 *10*10/60
P= 10^4
P=10000w
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