Question

water is filled in a flask up to a height of 20cm . The bottom of the flask is circular with radius 10cm . IF the atmospheric pressure is 1.01×10^5pa , find the first exerted by the water on the bottom. take g=10m/s^2and density of water =1000 kg/m^3.

Answer 1

volume of water in the tank, v=πr^2 h

as weight of liquid= d V g
here d is density,
V is volume of column,
g is acceleration due to gravity.

and pressure of water =weight / cross sectional area

so, pressure or thrust =dvg/πr^2
or, thrust =d ×(πr^2h)×g /πr^2
or, thrust = dhg=1000×0.2×10=2000=2×10^3Pa

so, total thrust = atmospheric pressure + pressure exerted by the weight of water column
so, total thrust =1.01×10^5 +2×10^3=10^3(101+2)
=103×10^3=1.03×10^3 Pa

Thanks.

Answer 2

prefer to attachment........