Water is filled in a flask upto a height of 20 cm. The bottom of the flask Is circular with radius 10 cm. If the atmospheric pressure is 1.013 x 10' Pa, find the force exerted by the water on the bottom. Take g=10 ms and density of water = 1000 kgm.
Answers
Answer:
the answer is 3243 N
Explanation:
h is height
r is radius
A is area
F is force
d is density
Pa is atmospheric pressure
P is total pressure
g is acceleration due to gravity
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Answer:
The force at the bottom of the flask 3234.2 N
Explanation:
Given,
- Water filled in the flask up to the height of 20 cm = 0.2 m
- The circular radius of the flask = 10 cm = 0.1 m
- The atmospheric pressure = 1.013 × 10⁵ Pa
- g = 10ms²
- Density of water = 1000 kgm⁻³
Solution:
The pressure at the surface of water = Atmospheric pressure P₀
The pressure at the bottom P = P₀ + hρg .....................(1)
Substitute the values in equation (1) we get,
P = (1.013 × 10⁵) + ( 0.2m × 1000 kgm⁻³ × 10ms²)
P = 103300
P = 1.03 × 10⁵ Pa
Area of the bottom of the flask = π r² ....................(2)
Substitute the values in equation (2) we get,
A = 3.14 × (0.1 m)²
A = 0.0314 m²
To find the force at the bottom of the flask:
F = P π r² ...........................................(3)
Substitute the values in equation (3) we get
F = (1.03 × 10⁵ Pa) × ( 0.0314 m² )
F = 3234.2 N
The force at the bottom of the flask 3234.2 N
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