Question

Water is filled in a right cylindrical tank with base radius 14 cm such that water level is 3 cm below the top when an iron ball is dropped in the tank3003 of water flows out find the radius of the ball​

Answer 1

Step-by-step explanation:

Given Water is filled in a right cylindrical tank with base radius 14 cm such that water level is 3 cm below the top when an iron ball is dropped in the tank 3003 of water flows out find the radius of the ball

• Given radius of base of cylinder = 14 cm
• We know that volume of cylindrical tank = π (14)^2 h cm^3
• Now water level is 3 cm below the top. So height will be (h – 3) cm^3
• When an iron ball is dropped in the tank, 3003 cc of water flows out.
• So volume of iron ball = volume of cylindrical tank – volume of water in the tank + 3003 cc
•                                     =[ π x 14^2 h – π x 14^2 (h – 3)] + 3003
•                                    = π (14^2 h – 14^2 h + 196 x 3) + 3003
•                                     = 588 π + 3003
•                                    = 1848 + 3003
•                                    = 4851 cm^3
• Now volume of iron ball = 4/3 π r^3
• So 4/3 π r^3 = 4851 cm^3
•   4/3 x 22/7 x r^3 = 4851
• So r^3 = 4851 x 3 x 7 / 4 x 22
•            = 1157.625
• Or r = 10.5 cm

Therefore the radius of the iron ball is 10.5 cm

Reference link will be

https://brainly.in/question/2022656

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