water is filled in a right cylindrical tank with base radius 14 cm, such that water
level is 3 cm below the top. When an iron ball is dropped in the tank, 3003 cm of
water flows out. Find the radius of the ball.
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Reading the question very carefully
We can understand that
Volume of the iron Ball = Volume of water displaced by the Ball
thus
if the radius of ball is r
then Volume of the spherical ball = 4/3 pi r^3
Thus
4/3 pi r^3 = 3003
pi r^3 = 9009/4
r^3 = 9009/4 * 3.14
r = 41.35 Cm
thus radius of ball is 41.35 Cm
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