Physics, asked by PARTHCHOUBISA, 1 year ago

water is filled up to same height in two identical closed container A and B contain IAS vacuum our the water while container B has air our the water at the same depth of both the containers there is an opening on which identical balloons A and B are attached is known as shown in the figure given below then

Answers

Answered by Anonymous
0

According to the circumstances mentioned in the question,water is filled up to same height in two identical closed container A and B contain IAS vacuum our the water while container B has air our the water at the same depth of both the containers there is an opening on which identical balloons A and B are attached.

In this situation the balloon B will bulge more in the water.

Answered by mindfulmaisel
0

"Given:

Both the containers have same height of water.        

Solution:

Answer: (2). Balloon B will bulge more than Balloon A.

Pressure due to the water (Static pressure),

                    P = \rho gh;

          Where, \rho is the density of the given fluid;

                       g is the acceleration due to gravity;

                       h is the static height.

Both A and B have same fluid at same height. So, the static pressure due to height remains same. But the additional air on the top surface above the water will cause extra pressure than the vacuum in the container A.

Thus, it is confirmed that the balloon B will bulge more than balloon A."

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