Question

Water is filled upto same height in two identical closed containers A and B. Container A has vacuum over the water while container B has air over the water. At the same depth of both the containers there is an opening on which identical balloons Aand B are attached as shown in the figure given below. Then

(1) Balloon-A will bulge more than balloon-B

(2) Balloon-B will bulge more than balloon-A

(3) Both the balloons will bulge equally

(4) None of the balloons will bulge

Answer 1

2.  Answer is 2 because air has more pressure than vacuum.

Answer 2

Answer: Option B: Balloon B will bulge more than Balloon A.

Explanation:

The bulging of Balloon would depend on the amount of pressure above the point where balloon is fixed. The pressure at a point due to fluid above it is given by:

$P=\rho h g$

here $\rho$ is the density of the fluid, h is the height to which it is filled and g is the acceleration due to gravity.

In both the containers, the level of water is same. Hence, pressure due to water is same in both the containers. Now, in container B, there is additional air present above water but there is vacuum in A. Hence, balloon B would experience more pressure and bulge out more.