Science, asked by surbhi2351, 1 year ago

Water is filled upto same height in two identical closed containers A and B. Container A has vaccum over the water while container B has air over the water. At the same depth of both the containers there is an an opening on which identical baloons A and B are attached. which balloon is bulge A and B.

Answers

Answered by UnknownDude
1
[0010001111]... Hello User... [1001010101]
Here's your answer...

The second container B will cause a greater bulge in the balloon.

Here's how.

The balloons are attached at the same depth of each container. Let that height be h.

So the pressure by the liquid in each case will be dhg, where d is the density of the liquid (water here) and g is the acceleration due to gravity.

However, the total pressure at those points will be different.

In container A, the pressure will be dhg.

In container B, the pressure will be dhg + P, where P is the pressure exerted by air on the liquid.

This added pressure causes a bigger bulge in the balloon attached to container B.

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Answered by sunilpalIwal851
1

Hi.

The balloon with air filled container will bulge first. Because in. Case. Of. The. Vacuum. One..

The pressure is zero and the water should also cover the area of vaccum before coming out. Compared to this the air one has so pressure by which it can enable the balloon to bulge first. But it takes time

Hope you have got ur ans

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UnknownDude: I've learnt what people usually mean when they say stuff here
surbhi2351: actually your answer is correct but u use some code numbers which I can't understand.
surbhi2351: can I know your class
UnknownDude: I'm in eleventh
UnknownDude: And what code numbers?
UnknownDude: You mean [0010001111]?
surbhi2351: yaa
surbhi2351: I will talk to u later i am in hospital
UnknownDude: Alright
UnknownDude: [0010001111] is just my style of answering. It doesn't really mean anything
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