Water is filled upto same height in two identical closed containers A and B. Container A has vaccum over the water while container B has air over the water. At the same depth of both the containers there is an an opening on which identical baloons A and B are attached. which balloon is bulge A and B.
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The second container B will cause a greater bulge in the balloon.
Here's how.
The balloons are attached at the same depth of each container. Let that height be h.
So the pressure by the liquid in each case will be dhg, where d is the density of the liquid (water here) and g is the acceleration due to gravity.
However, the total pressure at those points will be different.
In container A, the pressure will be dhg.
In container B, the pressure will be dhg + P, where P is the pressure exerted by air on the liquid.
This added pressure causes a bigger bulge in the balloon attached to container B.
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Here's your answer...
The second container B will cause a greater bulge in the balloon.
Here's how.
The balloons are attached at the same depth of each container. Let that height be h.
So the pressure by the liquid in each case will be dhg, where d is the density of the liquid (water here) and g is the acceleration due to gravity.
However, the total pressure at those points will be different.
In container A, the pressure will be dhg.
In container B, the pressure will be dhg + P, where P is the pressure exerted by air on the liquid.
This added pressure causes a bigger bulge in the balloon attached to container B.
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//This is your friendly neighbourhood UnknownDude
Answered by
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Hi.
The balloon with air filled container will bulge first. Because in. Case. Of. The. Vacuum. One..
The pressure is zero and the water should also cover the area of vaccum before coming out. Compared to this the air one has so pressure by which it can enable the balloon to bulge first. But it takes time
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