Water is flowing at 0.7m/s through a circular pipe of internal diameter of 2cm into cylindrical tank,the radius of whose base is 40cm. Find the increase in water level in 30 minutes
Answers
Answered by
5
Let Water level rise in 0.5 hr = x cm
And
We know Volume of cylinder = , So
Here Radius r = 1 cm and h = 0.7 m = 70 cm ( As we know 1 m = 100 cm )
As given Water is flowing at the rate of 0.7 m per sec
So,
Volume of water flowing through the pipe in one sec =
In 0.5 hours, water flowing through the pipe = ( We know 1 hour = 60 minutes and 1 minute = 60 sec , So 0.5 hr = 30 minutes = 1800 sec )
Volume of water in the tank after 0.5 hours = Volume of the cylindrical tank the radius of whose base is 40 cm and height is x cm ( as we assumed )
So,
Volume of the cylindrical tank =
So,
So,
Water level rise in 0.5 hr = 78.75 cm ( Ans )
Answered by
20
The volume of water raised after 30 mins in the tank is given as 395.64 litres
Given :
Diameter of cylindrical pipe = 2cm
The rate of water flow = 0.7m/sec
To Find :
Much water rise in the tank in half and hour
Formula Applied :
Solution :
As by given ,
Cross section area of pipe =Area of circle=
Diameter of pipe = 2cm
Radius =
Area of circle =
Hence the volume of water flowing per second ,
Hence of water is flowing per second.
The amount of water flowing for 30 mins is given as,
Hence the volume of water raised after 30 mins in litres is given as 395.64 litres
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