Math, asked by anshitagupta0677, 7 months ago

Water is flowing at 7m/sec through a circular pipe of internal diameter 2 cm into a cylindrical tank the radius of whose base is 40cm. Find the increased in water level in 30 minutes. OR A toy is in the form of a cone mounted on a hemisphere of radius 3.5cm. If the total height of the toy is 15.5cm, find its total surface area.(use =22/7)

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Answers

Answered by rajeevr06
0

Answer:

In 1 sec., volume of water store in tank =

\pi \times  {1}^{2}  \times 700 \:  {cm}^{3}  = 700\pi {cm}^{3}

so in 30 min, volume of water become

700\pi \times 30 \times 60  {cm}^{3}

so increase in water level =

 \frac{700\pi \times 30 \times 60}{\pi \times 40 \times 40}  =  \frac{7 \times 15 \times 15}{2}  = 787.5cm = 7.875 \: meter

Ans

Answered by priya266315
0

Step-by-step explanation:

In 1 sec., volume of water store in tank =

\pi \times {1}^{2} \times 700 \: {cm}^{3} = 700\pi {cm}^{3}π×1

2

×700cm

3

=700πcm

3

so in 30 min, volume of water become

700\pi \times 30 \times 60 {cm}^{3}700π×30×60cm

3

so increase in water level =

\frac{700\pi \times 30 \times 60}{\pi \times 40 \times 40} = \frac{7 \times 15 \times 15}{2} = 787.5cm = 7.875 \: meter

π×40×40

700π×30×60

=

2

7×15×15

=787.5cm=7.875meter

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