Question

WATER IS FLOWING AT A RATE OF 2.52KM/HR THROUGH A CYLINDRICAL PIPE INTO A CYLINDRICAL TANK,THE RADIUS OF WHOSE BASE IS 40CM.IF THE INCREASE IN THE LEVEL OF WATER IN THE TANK ,IN THE HALF OF THE HOUR IS 3.15M , FIND THE INTERNAL DIAMETER OF THE PIPE

Answer 1

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Answer 2

Answer:

Internal Diameter of Pipe =4cm

Step-by-step explanation:✪ ✫ ✬ ✭ ✮ ✯

Increase in level of water in tank in half hour =3.15m

⇒Increase in level of water in 1hour =6.3m

Or increase in level of water in cylindrical tank  =6.3m/h

So Volume of water in tank in 1hour =πr²h

given that radius of cylindrical tank =40cm =0.4m

Volume of water =(22/7)(0.4)²×6.3

=22×(0.16)×(0.9)

=22×1.44

=3.168m³

It means 3.168m³ Volume of water increases per hour.

So Volume of water flowing thorough Pipe =3.168m³/h

Or (2.52km/h)×cross sectional area of pipe =3.168m³/h

Or (2520m/h)×πr² =3.168m³/h

Or 360×22r²=3.168

Or r² =3.168/7920

Or r²=0.0004m²

⇒ r=+0.02m=2cm  (radius is always +ve)

D=2r=4cm  ✪ ✫ ✬ ✭ ✮ ✯