Water is flowing at the rate of 0.7 m/sec through a circular pipe whose internal diameter is 2 cm into 4 a cylindrical tank, the radius of whose base is 40 cm. Determine the increase in the level of water in half hour.
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Answer:
volume of tank = π r^2 h
= π × 0.4 × 0.4 × h
volume of water flow = speed × time × area of cross section
= 0.7 × 30 × 60 × π ×0.01 × 0.01
volume of tank = volume of water flow
π × 0.4 × 0.4 × h = 0.7 × 30 × 60 × π × 0.01 × 0.01
after solving this
h = o.7875 metre
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