Water is flowing at the rate of 0.7 m/sec through a circular pipe whose internal diameter is 2 cm into a cylindrical tank, the radius of whose base is 40 cm. Determine the increase in the level of water in half hour.
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If we see the rate, it's 0.7m/sec
that means 70 cm in one second
So,in one second volume of water in pipe = π r² h
= π×(1)² × 70 = 70π
in 30 min,volume = 30×60×70π = 126000π
this volume = volume of tank
⇒π×(40)² ×H = 126000 π
⇒H =126000/1600 = 78.75 cm
that means 70 cm in one second
So,in one second volume of water in pipe = π r² h
= π×(1)² × 70 = 70π
in 30 min,volume = 30×60×70π = 126000π
this volume = volume of tank
⇒π×(40)² ×H = 126000 π
⇒H =126000/1600 = 78.75 cm
muskansabharwal30:
why did you multiplied 30x60x70Π
to change 30 min into second...we have to multiply by 60
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the pic given below by a teacher
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