Question

.Water is flowing at the rate of 0.7 m/sec through a circular pipe whose internal
diameter is 2 cm into a cylindrical tank, the radius of whose base is 40 cm.
Determine the increase in the level of water in half hour.

Answer 1

Answer:

78.75 cm

Step-by-step explanation:

Length of water that flows out in 30 minutes

= (0.7 X 100 X 60 X 30) cm  (Here we multiplied 100 for conversion into cm, 60 for conversion in minutes and 30 for half an hour)

= 126000 cm

Volume of water that flows out in 30 minutes

=  (1)2 x 126000 cm3

= 126000 cm3

Let the depth of water in the tank be x cm

Volume of water in tank

=  (40)2 X x cm3

[1/2]

According to the question

 (40)2 X x = 126000

 x = 78.75 cm

Answer 2

Answer:

78.75 Centimetres

Step-by-step explanation:

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