Math, asked by siddhanshGupta, 1 year ago

Water is flowing at the rate of 15 km per hour through a pipe of diameter 14cm into a rectangular tank which is 50 m long and 44 m wide. Find the time in which the level of water in the tank will rise by 21 em.​

Answers

Answered by Nitin2112
1

Answer:20 min

Step-by-step explanation:

Given dimensions of rectangular tank=50 x 44 x 21

d of pipe=14

r=7

v=15 km/hr=15000 m/hr

t=?

according to question

volume of tank= area x v x t

50 x 44 x 21=22/7 x 7 x 7 x 15000 x t

t=1/5

t=1/5 x 60=20 min

hope its correct <3

Answered by BrainlyVirat
5

Given

Diameter of cylinder = 14 cm

Radius = r = 7 cm = 7/100 metres

Volume of cylinder = πr^2h

Volume of water flowing through the cylindrical pipe in 1 hour at the rate of 15km/hr =

( 15 km = 15000 metres )

 \tt{ \frac{22}{7}  \times  \frac{7}{100}  \times  \frac{7}{100}  \times 15000}

= 231 cu.metres

We know that,

Volume of cuboid = lbh

Therefore,

Volume of water in the tank =

( 21 cm = 21/100 metres )

 \tt{50 \times 44 \times  \frac{21}{100}  = 462}

Thus,

Time taken = (462/231)

= 2 hours

Therefore, the time in which the level of water in the tank will rise by 21 cm is 2 hours.

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