Question

Water is flowing at the rate of 15
through a pipe of diameter 14 cm
cuboidal pond which is 50 m long
ter 14 cm into a
s 50 m long and 44 m
wide. By what level water will rise in 2 /3hours
of time?
​

Answer 1

Answer:2 hrs

Step-by-step explanation:

Let the level of water in the pond rises by 21 cm in t hours.

Speed of water = 15 km/hr

Diameter of the pipe = 14/100 m

Radius of the pipe (r) = 7/100 m

Volume of water flowing out of the pipe in 1 hour

= π r 2 h

= (22/7) x (7/100) x (7/100) x 15000

= 231 m3

Volume of water flowing out of the pipe in t hours = 231 t m3.

Volume of water in the cuboidal pond

= 50 x 44 x (21/100)

= 462 m3

Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond

So, 231 t = 462

t = 2

Thus, the required time is 2 hours.

PLEASE MARK AS BRAINLIEST.Whoops,forgot caps were on lmao