Question

water is flowing at the rate of 15km/hour through a of diameter 14 CM into a cuboidal pond which is 50m long and 44m wide. In what time will the level of water in the pond rise by 21cm? ​

Answer 1

HEY MATE

Let the level of water in the pond rises by 21 cm

in t hours.

Speed of water 15 km/hr

Diameter of the pipe 14/100 m

Radius of the pipe (r) 7/100 m

Volume of water flowing out of the pipe in 1 hour

= (22/7) x (7/100) (7/100) x 15000

= 231 m3

Volume of water flowing out of the pipe in t hours

231t m3

Volume of water in the cuboidal pond

50 x 44 x (21/100)

= 462 m

Volume of water flowing out of the pipe in t hours =

Volume of water in the cuboidal pond

So, 231 t 462

t =2

thus, the required time is 2 hours

HOPE THIS ANSWER WILL HELP YOU

Answer 2

Step-by-step explanation:

Answer:

→ Time = 2 hours .

Step-by-step explanation:

Suppose, the level of water in the pond rises by 21 cm in 'x' hours.

→ Speed of water flowing through a pipe = 15 km/hr .

→ Diameter of the pipe = 14/100 m .

Then, Radius of the pipe (r) = 7/100 m .

∵ Volume of water flowing out of the pipe in 1 hour

= πr²h .

= (22/7) x (7/100) x (7/100) x 15000 .

= 231 m³ .

→

Volume of water flowing out of the pipe in 'x' hours = 231x m³.

∵ Volume of water in the cuboidal pond = lbh .

= 50 x 44 x (21/100) .

= 462 m³ .

∵ Volume of water flowing out of the pipe in 'x' hours = Volume of water in the cuboidal pond raised by 21 cm .

∵ 231x = 462 .

⇒ x = $\frac{462}{231}$

.

∴ x = 2 .......

Therefore, the required time is 2 hours