Question

Water is flowing at the rate of 15km/hr through a cylindrical pipe of radius 7cm into a rectangular tank which is 50m long and 44m wide. In how many hours will the water level of the tank raise by 21cm

Answer 1

time taken by water=15000x=length
radius= 7 /100m
volume= pie 73.5x =11×21x

volume of rectangular park=50×44×21/100
22×21


there fore
11×21x = 22 × 21
ie x= 2
the answer is two hours

Answer 2

Step-by-step explanation:

Answer:

→ Time = 2 hours .

Step-by-step explanation:

Suppose, the level of water in the pond rises by 21 cm in 'x' hours.

→ Speed of water flowing through a pipe = 15 km/hr .

→ Diameter of the pipe = 14/100 m .

Then, Radius of the pipe (r) = 7/100 m .

∵ Volume of water flowing out of the pipe in 1 hour

= πr²h .

= (22/7) x (7/100) x (7/100) x 15000 .

= 231 m³ .

→

Volume of water flowing out of the pipe in 'x' hours = 231x m³.

∵ Volume of water in the cuboidal pond = lbh .

= 50 x 44 x (21/100) .

= 462 m³ .

∵ Volume of water flowing out of the pipe in 'x' hours = Volume of water in the cuboidal pond raised by 21 cm .

∵ 231x = 462 .

⇒ x = $\frac{462}{231}$

.

∴ x = 2 .

Therefore, the required time is 2 hours