Math, asked by prapti3054, 1 year ago

water is flowing at the rate of 15km/hr through a cylindrical pipe of radius of 7cm into a rectangular tank which is 50m long and 44m wide. in how many hours will the water level in the tank raise by 21cm.

Answers

Answered by srisuranamotorsfinan
0

Answer:

Step-by-step explanation:

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Answered by Anonymous
53

Step-by-step explanation:

Answer:

→ Time = 2 hours .

Step-by-step explanation:

Suppose, the level of water in the pond rises by 21 cm in 'x' hours.

→ Speed of water flowing through a pipe = 15 km/hr .

→ Diameter of the pipe = 14/100 m .

Then, Radius of the pipe (r) = 7/100 m .

∵ Volume of water flowing out of the pipe in 1 hour

= πr²h .

= (22/7) x (7/100) x (7/100) x 15000 .

= 231 m³ .

→ Volume of water flowing out of the pipe in 'x' hours = 231x m³.

∵ Volume of water in the cuboidal pond = lbh .

= 50 x 44 x (21/100) .

= 462 m³ .

∵ Volume of water flowing out of the pipe in 'x' hours = Volume of water in the cuboidal pond raised by 21 cm .

∵ 231x = 462 .

⇒ x =  \frac{462}{231}

∴ x = 2 .

Therefore, the required time is 2 hours

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