Water is flowing at the rate of 15km per hour through a cylindrical pipe of diameter 14cm into a cuboid pond which is 50 cm long and 44 metre wide . In what time to the level of water in pond rise by 21 cm .
Guys have a look on the points and plz step by step explanation .
Answers
In cylinder,
r=7cm=0.7
ml=15km =15000mIn tank,
l=50
mb=44
mh=0.21m
Vol.of water in tank=lbh =50*44*0.21 =462m³
Height of cylindrical pipe=Vol. / πr² =462/(0.07)²(22/7) =462/0.0154 =30000mTime = 30000/15000 = 2 hours
Step-by-step explanation:
let the level of water in the pond rises by 21 cm in t hours.
Speed of water = 15 km/hr
Diameter of the pipe = 14/100 m
Radius of the pipe (r) = 7/100 m
Volume of water flowing out of the pipe in 1 hour
= π r 2 h
= (22/7) x (7/100) x (7/100) x 15000
= 231 m3
Volume of water flowing out of the pipe in t hours = 231 t m3.
Volume of water in the cuboidal pond
= 50 x 44 x (21/100)
= 462 m3
Volume of water flowing out of the pipe in t hours = Volume of water in the cuboidal pond
So, 231 t = 462
t = 2
Thus, the required time is 2 hours.