Question

Water is flowing at the rate of 15km per hour through a pipe of diameter 14cm into a rectangular tank which is 50m long and 44m wide. Find the time in which the level of water in the tank will rise by 21cm.

Answer 1

Hello Mate!

Volume of water in tank = 50 m × 44 m × 0.21 m

= 462 m³

Now, volume of water flowed from pipe = volume of cylindrical pipe

Volume of Cylindrical pipe = πr²h

Volume of Cylindrical pipe = 22/7 × (14/2)² × 15 km/hr

= 22/7 × 14/2 × 14/2 cm ² × 15000 m/hr

= 154 cm² × 15000 m/hr

Since 1 cm² = 1/10000 m²

= 154/10000 m² = 0.0154 m²

= 0.0154 m² × 15000 m/hr

= 231 m³/hr

Let the time taken be t.

231 m³/hr × t = 462 m³

t = 2 hrs

Hence time taken is 2 hrs

Thanks!!!

Have great future ahead!

Answer 2

Step-by-step explanation:

Answer:

→ Time = 2 hours .

Step-by-step explanation:

Suppose, the level of water in the pond rises by 21 cm in 'x' hours.

→ Speed of water flowing through a pipe = 15 km/hr .

→ Diameter of the pipe = 14/100 m .

Then, Radius of the pipe (r) = 7/100 m .

∵ Volume of water flowing out of the pipe in 1 hour

= πr²h .

= (22/7) x (7/100) x (7/100) x 15000 .

= 231 m³ .

→

Volume of water flowing out of the pipe in 'x' hours = 231x m³.

∵ Volume of water in the cuboidal pond = lbh .

= 50 x 44 x (21/100) .

= 462 m³ .

∵ Volume of water flowing out of the pipe in 'x' hours = Volume of water in the cuboidal pond raised by 21 cm .

∵ 231x = 462 .

⇒ x = $\frac{462}{231}$

∴ x = 2 .

Therefore, the required time is 2 hours