Question

water is flowing at the rate of 2.52km/hours through a cylindrical pipe into a cylindrical tank the radius of whose base is 40 cm if the increase in level of water in the tank in half an hour is 3.15 m find the internal diameter of the pipe

Answer 1

Here is the detailed answer for your query.

Answer 2

Answer:

Internal Diameter of Pipe =4cm

Step-by-step explanation:✪ ✫ ✬ ✭ ✮ ✯

Increase in level of water in tank in half hour =3.15m

⇒Increase in level of water in 1hour =6.3m

Or increase in level of water in cylindrical tank  =6.3m/h

So Volume of water in tank in 1hour =πr²h

given that radius of cylindrical tank =40cm =0.4m

Volume of water =(22/7)(0.4)²×6.3

=22×(0.16)×(0.9)

=22×1.44

=3.168m³

It means 3.168m³ Volume of water increases per hour.

So Volume of water flowing thorough Pipe =3.168m³/h

Or (2.52km/h)×cross sectional area of pipe =3.168m³/h

Or (2520m/h)×πr² =3.168m³/h

Or 360×22r²=3.168

Or r² =3.168/7920

Or r²=0.0004m²

⇒ r=+0.02m=2cm  (radius is always +ve)

D=2r=4cm  ✪ ✫ ✬ ✭ ✮ ✯