Water is flowing at the rate of 5 km/hour through a pipe of diameter 14 cm into a rectangular tank of
dimensions 50 m x 44 m. Find the time in which the level of water in the tank will rise by 7 cm.
Answers
FINAL ANSWER:-
→ Time = 2 hours .
SOLUTION:-
Suppose, the level of water in the pond rises by 21 cm in 'x' hours.
→ Speed of water flowing through a pipe = 15 km/hr .
→ Diameter of the pipe = 14/100 m .
Then, Radius of the pipe (r) = 7/100 m .
∵ Volume of water flowing out of the pipe in 1 hour
= πr²h .
= (22/7) x (7/100) x (7/100) x 15000 .
= 231 m³ .
→ Volume of water flowing out of the pipe in 'x' hours = 231x m³.
∵ Volume of water in the cuboidal pond = lbh .
= 50 x 44 x (21/100)
= 462 m³
∵ Volume of water flowing out of the pipe in 'x' hours = Volume of water in the cuboidal pond raised by 21 cm .
∵ 231x = 462 .
⇒ x = 462/231 .
∴ x = 2 .
Therefore, the required time is 2 hours.
Hence, it is solved .
THANKS
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