Math, asked by yadavajit1882, 1 year ago

Water is flowing at the rate of 5km/hr through a pipe of diameter 14 cm into a rectangular tank of dimensions 50m*44m . find the time in which the level of water in the tank will rise by 7cm

Answers

Answered by BEJOICE
9

volumetric \: flow \: rate \: of \: water \\  = pipe \: cross \: sectional \: area \times velocity
flow \: rate =  \\  \frac{\pi}{4}  \times  {( \frac{14}{100} )}^{2}  \times 5000 = 77 \:  {m}^{3}
Volume of water in tank when it reaches 7 cm,
volume  = 50 \times 44 \times  \frac{7}{100}  = 154 \:  {m}^{3}
time \: to \: fill =  \\  \frac{volume}{flow \: rate}  =  \frac{154}{77}  = 2 \: hrs
Answered by jyashaswylenka
9

Answer:

Step-by-step explanation:

Convert all to metres:

5 km = 5000 m

14 cm = 0.14 m

7 cm = 0.07 m

Find the radius:

Radius = Diameter ÷ 2

Radius = 0.14 ÷ 2 = 0.07 m

Find the amount of water that flowed out in an hour:

Volume = πr²h

Volume = π (0.07)² (5000) = 77 m³ per hour

Find the amount of water needed in the tank:

Volume = Length x Breadth x Height

Volume = 50 x 44 x 0.07 = 154 m³

Find the number of hours needed:

Number of hours = 154 ÷ 77 = 2 hours

Answer: It takes 2 hours to fill up the tank to rise by 7 cm

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