Question

Water is flowing at the rate of 7 m/s through a circular pipe of internal diameter is 2 cm into a
cylindrical tank. The radius of cylindrical tank is 40 cm. Find the increase in water level in half an hour. ​

Answer 1

Step-by-step explanation:

Length of pipe = H = Speed x time = 7m x 1800s

Radius of pipe = r= 1/100 m

Radius of tank = R = 40/100 m = 2/5 m

Increase in water level = h

Volume of pipe = Volume of tank

πr^2H = πR^2h

r^2H = R^2h

(1/100)^2 x 7 x 1800 = (2/5)^2 x h

(1/10000 x 7 x 1800) ÷ (4/25) = h

h = 78.75 m (is the increase in water level)

Hence Found

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